4x^2+20+12=0

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Solution for 4x^2+20+12=0 equation: 



4x^2+20+12=0

We add all the numbers together, and all the variables

4x^2+32=0

a = 4; b = 0; c = +32;
Δ = b2-4ac
Δ = 02-4·4·32
Δ = -512
Delta is less than zero, so there is no solution for the equation

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